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Simplifying x2 + 3.5x = 135 Reorder the terms: 3.5x + x2 = 135 Solving 3.5x + x2 = 135 Solving for variable 'x'. Reorder the terms: -135 + 3.5x + x2 = 135 + -135 Combine like terms: 135 + -135 = 0 -135 + 3.5x + x2 = 0 Begin completing the square. Move the constant term to the right: Add '135' to each side of the equation. -135 + 3.5x + 135 + x2 = 0 + 135 Reorder the terms: -135 + 135 + 3.5x + x2 = 0 + 135 Combine like terms: -135 + 135 = 0 0 + 3.5x + x2 = 0 + 135 3.5x + x2 = 0 + 135 Combine like terms: 0 + 135 = 135 3.5x + x2 = 135 The x term is 3.5x. Take half its coefficient (1.75). Square it (3.0625) and add it to both sides. Add '3.0625' to each side of the equation. 3.5x + 3.0625 + x2 = 135 + 3.0625 Reorder the terms: 3.0625 + 3.5x + x2 = 135 + 3.0625 Combine like terms: 135 + 3.0625 = 138.0625 3.0625 + 3.5x + x2 = 138.0625 Factor a perfect square on the left side: (x + 1.75)(x + 1.75) = 138.0625 Calculate the square root of the right side: 11.75 Break this problem into two subproblems by setting (x + 1.75) equal to 11.75 and -11.75.Subproblem 1
x + 1.75 = 11.75 Simplifying x + 1.75 = 11.75 Reorder the terms: 1.75 + x = 11.75 Solving 1.75 + x = 11.75 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-1.75' to each side of the equation. 1.75 + -1.75 + x = 11.75 + -1.75 Combine like terms: 1.75 + -1.75 = 0.00 0.00 + x = 11.75 + -1.75 x = 11.75 + -1.75 Combine like terms: 11.75 + -1.75 = 10 x = 10 Simplifying x = 10Subproblem 2
x + 1.75 = -11.75 Simplifying x + 1.75 = -11.75 Reorder the terms: 1.75 + x = -11.75 Solving 1.75 + x = -11.75 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-1.75' to each side of the equation. 1.75 + -1.75 + x = -11.75 + -1.75 Combine like terms: 1.75 + -1.75 = 0.00 0.00 + x = -11.75 + -1.75 x = -11.75 + -1.75 Combine like terms: -11.75 + -1.75 = -13.5 x = -13.5 Simplifying x = -13.5Solution
The solution to the problem is based on the solutions from the subproblems. x = {10, -13.5}
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